limits approaching 0

[jbreu]

3x + 3xcos(3x) / 8sin(3x)cos(3x) =


3x / 8sin(3x)cos(3x) + 3x / 8sin(3x)

I understand how the numerator simplifies, but why is cos(3x) simplified from the denominator in the second fraction?

 

[Deleted member 4993]

3x + 3xcos(3x) / 8sin(3x)cos(3x) =


3x / 8sin(3x)cos(3x) + 3x / 8sin(3x)

I understand how the numerator simplifies, but why is cos(3x) simplified from the denominator in the second fraction?

\(\displaystyle \frac{3*x + 3*x*cos(3*x)}{8*sin(3*x)*cos(3*x)} \ =\)

\(\displaystyle \ \frac{3*x}{8*sin(3*x)*cos(3*x)} + \frac{3*x*cos(3*x)}{8*sin(3*x)*cos(3*x)} \ =\)

\(\displaystyle \ \frac{3*x}{8*sin(3*x)*cos(3*x)} + \frac{3*x}{8*sin(3*x)} \ =\)