limit

Multiply top and bottom by the conjugate, \(\displaystyle \sqrt{x+9}+3\)

Then it reduces down to something you can deal with.

By the way, I assume you mean \(\displaystyle \frac{\sqrt{x+9}-3}{x}\).

You have \(\displaystyle \sqrt{x+9}-\frac{3}{x}\) written.

That is why grouping symbols are important.
 
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