limit

[Ryan Rigdon]

i need help finding this limit.

lim (as x goes to -3+) (x^2)/((x+3)(6+x))

all i have been able to do is the following

lim (as x goes to -3+) x^2 = 9


lim (as x goes to -3+) x+3 = 0


lim (as x goes to -3+) 6+x = 3


i think the limit would be - infinity but something tells me i am wrong.

 

[Ryan Rigdon]

i found the limit to be +infinity.


what program do i need to use in order to put it on here like it was just out of the book.

 

[galactus]

Yes, it is \(\displaystyle {\infty}\)

You do not need a program to get LaTex to display. You can type in the code.

Here is yours:

\(\displaystyle \lim_{x\to -3^{+}}\frac{x^{2}}{(x+3)(x+6)}\)

To see what I typed to make it display like this, click on 'quote' in the upper right corner of this post.

 

[Ryan Rigdon]

Yes, it is \(\displaystyle {\infty}\)

You do not need a program to get LaTex to display. You can type in the code.

Here is yours:

\(\displaystyle \lim_{x\to -3^{+}}\frac{x^{2}}{(x+3)(x+6)}\)

To see what I typed to make it display like this, click on 'quote' in the upper right corner of this post.

thanx galactus. will give that a shot with my next question.