Hello, I want to solve the limit
lim x->inf ((sqrt(x))^lnx) / e^x
My thought was to apply the natural logarithm function on both the numerator and the denominator to simplify the exponent part on the numerator then apply L'hopital rule:
= lim x->inf ln[((sqrt(x))^lnx)] / ln[e^x] = lim x->inf (lnx)(ln(sqrtx)) / x = ... = 0.
Can you tell me if applying the natural logarithm function can be done this way?
Thanks
lim x->inf ((sqrt(x))^lnx) / e^x
My thought was to apply the natural logarithm function on both the numerator and the denominator to simplify the exponent part on the numerator then apply L'hopital rule:
= lim x->inf ln[((sqrt(x))^lnx)] / ln[e^x] = lim x->inf (lnx)(ln(sqrtx)) / x = ... = 0.
Can you tell me if applying the natural logarithm function can be done this way?
Thanks