Limit Problem

mop969

New member
Joined
Oct 10, 2008
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29
What are the steps to find the limit of this problem?


limit as t approaches 0 of:

(1/t) - (1/(t^2+t))
 
limt0[1t1t2+t]=1t1t(t+1)=(t+1)(t+1)1t1t(t+1)=1t+1\displaystyle \lim_{t\to 0}\left[\frac{1}{t}-\frac{1}{t^{2}+t}\right]=\frac{1}{t}-\frac{1}{t(t+1)}=\frac{(t+1)}{(t+1)}\cdot \frac{1}{t}-\frac{1}{t(t+1)}=\frac{1}{t+1}


Now, we merely have limt01t+1\displaystyle \lim_{t\to 0}\frac{1}{t+1}

Can you see what the limit is now?. Since the function is continuous, just sub in x=0.
 
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