limit problem - how to get zero out of denominator?

[PaulKraemer]

Hi,

I have no idea how to go about solving the following problem:

lim as h->0 of (4 - sqrt (16 + h)) / h

I assume I have to do something to get rid of the h in the denominator, but I have no idea how to go about this. If anyone could give me a clue, I'd really appreciate it.

Thanks in advance,
Paul

 

[galactus]

Multiply top and bottom by the conjugate of the numerator. This will rationalize the numerator and you can cancel h's.

That is, multiply top and bottom by \(\displaystyle 4+\sqrt{16+h}\)

 

[PaulKraemer]

Thank you galactus - that was a big help!

Paul