Limit of trigonometric sequence

[char5059]

I am trying to determine the limit of the sequence (a sub n) a sub n =arctan(1/3n) from n=1 to infinity. On the calculator it seems like the answer is 90 but this appears to be incorrect. Any help is appreciated. Thanks.

 

[galactus]

You appear to be correct. It approaches \(\displaystyle \L\\\frac{\pi}{2}\)

Which is 90.