Limit of a function

kidia

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Apr 11, 2006
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Please can any body help me on this function

Considering the two path approach,show that the function have no limit as (x,y)\(\displaystyle \rightarrow\)(0,0)

a)f(x,y)=\(\displaystyle \frac{x^4}{x^4+y^2}\)
 
One way to look at it is consider what the expression approaches at

(x,y)=(x,0).

The limit approaches 1 at all points on the x-axis except the origin:

\(\displaystyle \L\\\frac{x^{4}}{x^{4}+0}\).

Likewise, the values approach 0 as (x,y)=(0,y) approaches the origin

along the y-axis:

\(\displaystyle \L\\\frac{0}{0+y^{2}}\)

Since the values approach different numbers as (x,y) approaches the

origin, the limit at the origin does not exist.

If f(x,y) approaches different numbers as (x,y) approaches (a,b) along

different curves, then \(\displaystyle \L\\\lim_{(x,y)\to\(0,0)}f(x,y)\) does not

exist.
 
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