limit of (10^8)(x^5) + (10^6)(x^4)+ (10^4)(x^2) / ....

tsh44

Junior Member
Joined
Sep 4, 2005
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Hi I am having trouble with this particular limit

lim
xapproaches infinity

(10^8)(x^5) + (10^6)(x^4)+ (10^4)(x^2) / (10^9)(x^6) + (10^7)(x^5) + (10^5)(X^3)
 
Note that the degree of the denominator exceeds that of the numerator.
Divide both by \(\displaystyle x^6\).
 
tsh44 said:
(10^8)(x^5) + (10^6)(x^4)+ (10^4)(x^2) / (10^9)(x^6) + (10^7)(x^5) + (10^5)(X^3)
I will guess that you mean "x" and "X" to actually be the same variable (contrary to standard mathematical practice), But please note that tthe above means the following:

. . . . .10<sup>8</sup>x<sup>5</sup> + 10<sup>6</sup>x<sup>4</sup> + (10<sup>4</sup>x<sup>2</sup>) / (10<sup>9</sup>x<sup>6</sup>) + 10<sup>7</sup>x<sup>5</sup> + 10<sup>5</sup>x<sup>3</sup>

In other words:

. . . . .\(\displaystyle \L 10^8 x^5\, +\, 10^6 x^4\, +\, \frac{10^4 x^2}{10^9 x^6}\, +\, 10^7 x^5\, +\, 10^5 x^3\)

Is this what you meant? Or did you mean something more like the following?

. . . . .[10<sup>8</sup>x<sup>5</sup> + 10<sup>6</sup>x<sup>4</sup> + 10<sup>4</sup>x<sup>2</sup>] / [10<sup>9</sup>x<sup>6</sup> + 10<sup>7</sup>x<sup>5</sup> + 10<sup>5</sup>x<sup>3</sup>]

In other words:

. . . . .\(\displaystyle \L \frac{10^8 x^5\, +\, 10^6 x^4\, +\, 10^4 x^2}{10^9 x^6\, +\, 10^7 x^5\, +\, 10^5 x^3}\)

Please confirm or correct. When you reply, please include all of your work and reasoning so far. Thank you.

Eliz.
 
Sorry for not making that clear. I meant
[(10^8)(x^5) + (10^6)(x^4) + (10^4)(x^2)] / [(10^9)(x^6) + (10^7)(x^5) + (10^5)(x^3)]

pka said to divide by (x^6). So would that just leave 1/ 10^9 left?
 
tsh44 said:
pka said to divide by (x^6). So would that just leave 1/ 10^9 left?
How are you getting that?

Please be specific. Thank you.

Eliz.
 
I believe you get 0 because the denominator is larger than the numerator
 
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