Limit -- My own problem

lookagain

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Aug 22, 2010
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Using the fact that as limx0+(xx)=1\displaystyle \lim_{x\to0^+}(x^x) = 1 from below for sufficiently
small positive real numbers x\displaystyle x, determine the following limit:


limx0+[1(1xx)x]x\displaystyle \lim_{x\to 0^+}[1 - (1 - x^x)^x]^x
 
It would appear since limx0+xx=1\displaystyle \lim_{x\to 0^{+}}x^{x}=1 that

Try rewrting as:

elimx0+xln(1(1xx)x)\displaystyle e^{\huge\lim_{x\to 0^{+}}xln\left(1-(1-x^{x})^{x}\right)}

The limit in the power of e approaches 0 and we get e0=1\displaystyle e^{0}=1

The limit is 1 as well.
 
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