how would i solve limit as n approaches infinity of 5^(n+1)/7^n
D dirtypyjamas New member Joined May 16, 2013 Messages 5 May 16, 2013 #1 how would i solve limit as n approaches infinity of 5^(n+1)/7^n
D DrPhil Senior Member Joined Nov 29, 2012 Messages 1,383 May 16, 2013 #2 dirtypyjamas said: how would i solve limit as n approaches infinity of 5^(n+1)/7^n Click to expand... \(\displaystyle \displaystyle \dfrac{5^{n+1}}{7^n} = \dfrac{5 \times 5^n}{7^n} = 5 \left( \dfrac{5}{7} \right)^n \rightarrow \cdot \cdot \cdot\)
dirtypyjamas said: how would i solve limit as n approaches infinity of 5^(n+1)/7^n Click to expand... \(\displaystyle \displaystyle \dfrac{5^{n+1}}{7^n} = \dfrac{5 \times 5^n}{7^n} = 5 \left( \dfrac{5}{7} \right)^n \rightarrow \cdot \cdot \cdot\)
