Limit Help: (x - 1)/ Sqare root (x^2 - 1 ) as x -> 1

Marco

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1) I need to find the limit, as x approaches 1, of this expression
(x-1) / (sqrt(x^2 - 1)

do i need to conjugate the denominator like this?
(x-1) / (sqrt(x^2 - 1) • (sqrt(x^2 + 1) / (sqrt(x^2 + 1) ?

I know that I can conjugate IF the expression is like this :

(x-1)/ (sqrt (x^2) - 1) •
(sqrt (x^2) + 1) / (sqrt (x^2) + 1)

but in the 1st expression , I don't know what to do.

 
1) I need to find the limit, as x approaches 1, of this expression
(x-1) / (sqrt(x^2 - 1)

do i need to conjugate the denominator like this?
(x-1) / (sqrt(x^2 - 1) • (sqrt(x^2 + 1) / (sqrt(x^2 + 1) ?

I know that I can conjugate IF the expression is like this :

(x-1)/ (sqrt (x^2) - 1) •
(sqrt (x^2) + 1) / (sqrt (x^2) + 1)

but in the 1st expression , I don't know what to do.

In this case, you can conjugate - but that won't help. Instead:

(x-1) / sqrt(x^2 - 1) = [(x-1) / sqrt(x^2 - 1)] • sqrt(x^2 - 1) / sqrt(x^2 - 1) = [(x-1) / (x^2 - 1)] • sqrt(x^2 - 1) = [1 / (x + 1)] • sqrt(x^2 - 1)

Now take the limit....
 
1) I need to find the limit, as x approaches 1, of this expression
(x-1) / (sqrt(x^2 - 1)

do i need to conjugate the denominator like this?
(x-1) / (sqrt(x^2 - 1) • (sqrt(x^2 + 1) / (sqrt(x^2 + 1) ?
Note that the innards of the radical are a product; specifically, they're a difference of squares:

. . . . .\(\displaystyle x^2\, -\, 1\, =\, (x\, -\, 1)(x\, +\, 1)\)

This means that the expression can be restated as:

. . . . .\(\displaystyle \dfrac{x\, -\, 1}{\sqrt{\strut (x\, -\, 1)(x\, +\, 1)\,}}\, =\, \dfrac{\left(\sqrt{\strut x\, -\, 1\,}\right)^2}{\sqrt{\strut x\, -\, 1\,}\, \sqrt{\strut x\, +\, 1\,}}\)

Where does this lead? ;)
 
In this case, you can conjugate - but that won't help. Instead:

(x-1) / sqrt(x^2 - 1) = [(x-1) / sqrt(x^2 - 1)] • sqrt(x^2 - 1) / sqrt(x^2 - 1) = [(x-1) / (x^2 - 1)] • sqrt(x^2 - 1) = [1 / (x + 1)] • sqrt(x^2 - 1)

Now take the limit....

So, sqrt (x^2-1) / x+ 1 , how do I remove the radical?

or I will subtitute the x now by 1? , = sqrt (1^2 - 1) / 1+1 = sqrt(0)/ 2 = -> 0/2 <- am I correct? or not?

Thank you for replying :)
 
Note that the innards of the radical are a product; specifically, they're a difference of squares:

. . . . .\(\displaystyle x^2\, -\, 1\, =\, (x\, -\, 1)(x\, +\, 1)\)

This means that the expression can be restated as:

. . . . .\(\displaystyle \dfrac{x\, -\, 1}{\sqrt{\strut (x\, -\, 1)(x\, +\, 1)\,}}\, =\, \dfrac{\left(\sqrt{\strut x\, -\, 1\,}\right)^2}{\sqrt{\strut x\, -\, 1\,}\, \sqrt{\strut x\, +\, 1\,}}\)

Where does this lead? ;)

x-1/ sqrt (x^2 - 1) = Sqrt(x-1)^2 / (sqrt (x-1) (sqrt(x+2) = sqrt(x-1)/ sqrt (x+2) = [sqrt (x-1) / sqrt (x+2)] • [sqrt (x+2) / sqrt(x+2)] = sqrt(x-1) / x+2 • sqrt(x+2) = ( I don't know what to do next )

Thank you for Replying sir :)
 
So, sqrt (x^2-1) / x+ 1 , how do I remove the radical?

or I will subtitute the x now by 1? , = sqrt (1^2 - 1) / 1+1 = sqrt(0)/ 2 = -> 0/2 <- am I correct? or not?

Thank you for replying :)
How did you get that?!! Show detailed work.
 
How did you get that?!! Show detailed work.

(x-1) / sqrt(x^2 - 1) = [(x-1) / sqrt(x^2 - 1)] • sqrt(x^2 - 1) / sqrt(x^2 - 1) = [(x-1) / (x^2 - 1)] • sqrt(x^2 - 1) = [1 / (x + 1)] • sqrt(x^2 - 1) = [sqrt (x^2 -1 ) / x + 1 ], am I right sir? correct me sir if I am wrong,

thank you very much for your time :)
 
(x-1) / sqrt(x^2 - 1) = [(x-1) / sqrt(x^2 - 1)] • sqrt(x^2 - 1) / sqrt(x^2 - 1) = [(x-1) / (x^2 - 1)] • sqrt(x^2 - 1) = [1 / (x + 1)] • sqrt(x^2 - 1) = [sqrt (x^2 -1 ) / (x + 1) ], am I right sir? correct me sir if I am wrong,

thank you very much for your time :)
Must have those parentheses (). Otherwise meaning is changed.

Now take the limit .... what is stopping you?
 
Must have those parentheses (). Otherwise meaning is changed.

Now take the limit .... what is stopping you?

So, sqrt (x^2-1) / (x+1) , how do I remove the radical?

I will subtitute the x by 1 now sir?

sqrt ((1)^2 - 1) / (1+1) =
sqrt(0)/ 2 = 0/2 or 0,

the limit of
(x-1) / (sqrt(x^2 - 1) as x approaches 1 is 0

am I correct sir?

thank you for your time sir :)
 
So, sqrt (x^2-1) / (x+1) , how do I remove the radical?

I will subtitute the x by 1 now sir?

sqrt ((1)^2 - 1) / (1+1) =
sqrt(0)/ 2 = 0/2 or 0,

the limit of
(x-1) / (sqrt(x^2 - 1) as x approaches 1 is 0

am I correct sir?

thank you for your time sir :)
Correct
 
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