dyllusionist
New member
- Joined
- Feb 24, 2010
- Messages
- 1
I am trying to prove that the limit as (x,y) --> (1,0) of x+2y is equal to 1. I know we need to find a value of delta > 0 such that if 0 < sqrt((x-1)^2 + y^2) < delta, then abs(x + 2y - 1) < epsilon. However, I can't wrap my head around where to go next. Can anyone help? Thanks so much.