\(\displaystyle \sum_{n=3}^{\infty} \frac{2n+8}{[n ln(n)]^2 +4}\)
Can anyone give me some input as to what I could compare this to. At first glance, maybe I could do a limit comparison test with
bn= \(\displaystyle \frac{2n}{[n ln(n)]^2}\) , which would simplify to \(\displaystyle \frac{2}{n [ln(n)]^2}\)
Since n is the dominant term, would I compare it with the harmonic series of \(\displaystyle \frac{1}{n}\) ??
Any feedback appreciated. Thanks.
Can anyone give me some input as to what I could compare this to. At first glance, maybe I could do a limit comparison test with
bn= \(\displaystyle \frac{2n}{[n ln(n)]^2}\) , which would simplify to \(\displaystyle \frac{2}{n [ln(n)]^2}\)
Since n is the dominant term, would I compare it with the harmonic series of \(\displaystyle \frac{1}{n}\) ??
Any feedback appreciated. Thanks.
