lim,x->-2,(ln(3x+7))/(5x+10); lim,x->infty,(ln(3x+7))/(5x+10); lim,x->infty,(ln(x^2)+
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The limits in the image are:
\(\displaystyle \displaystyle \mathbf{5.3}\, \mbox{ }\, \lim_{x \rightarrow -2}\, \dfrac{\ln(3x\, +\, 7)}{5x\, +\, 10}\)
\(\displaystyle \displaystyle \mathbf{5.6}\, \mbox{ }\, \lim_{x \rightarrow +\infty}\, \dfrac{\ln(3x\, +\, 7)}{5x\, +\, 10}\)
\(\displaystyle \displaystyle \mathbf{5.7}\, \mbox{ }\, \lim_{x \rightarrow +\infty}\, \dfrac{\ln(x^2) + 1}{5\, +\, \ln(x)}\)
Thanks
< link to objectionable page removed >
The limits in the image are:
\(\displaystyle \displaystyle \mathbf{5.3}\, \mbox{ }\, \lim_{x \rightarrow -2}\, \dfrac{\ln(3x\, +\, 7)}{5x\, +\, 10}\)
\(\displaystyle \displaystyle \mathbf{5.6}\, \mbox{ }\, \lim_{x \rightarrow +\infty}\, \dfrac{\ln(3x\, +\, 7)}{5x\, +\, 10}\)
\(\displaystyle \displaystyle \mathbf{5.7}\, \mbox{ }\, \lim_{x \rightarrow +\infty}\, \dfrac{\ln(x^2) + 1}{5\, +\, \ln(x)}\)
Thanks
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