lim x->0 (x^x) L = lim x->0 (x^x) lnL = lim x->0 (x lnx) Is this OK so far?
T tdotgirl New member Joined Oct 4, 2006 Messages 17 Mar 12, 2007 #1 lim x->0 (x^x) L = lim x->0 (x^x) lnL = lim x->0 (x lnx) Is this OK so far?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Mar 12, 2007 #2 x*ln(x) = ln(x)/(1/x)
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Mar 12, 2007 #3 Hello, tdotgirl! limx→0(xx)\displaystyle \lim_{x\to0}(x^x)x→0lim(xx) L = limx→0(xx)\displaystyle L \:= \:\lim_{x\to0}(x^x)L=x→0lim(xx) ln(L) = limx→0(x⋅lnx)\displaystyle \ln(L)\: =\:\lim_{x\to0}(x\cdot\ln x)ln(L)=x→0lim(x⋅lnx) Is this OK so far? Click to expand... You're doing great!
Hello, tdotgirl! limx→0(xx)\displaystyle \lim_{x\to0}(x^x)x→0lim(xx) L = limx→0(xx)\displaystyle L \:= \:\lim_{x\to0}(x^x)L=x→0lim(xx) ln(L) = limx→0(x⋅lnx)\displaystyle \ln(L)\: =\:\lim_{x\to0}(x\cdot\ln x)ln(L)=x→0lim(x⋅lnx) Is this OK so far? Click to expand... You're doing great!
