lim [sqroot(x+5)-3]/(x-4)
x->4
i need help with this problem. I multiplied by the conjugate [sqroot(x+5)+sqroot(x)]/ [sqroot(x+5)+sqroot(x)] and got x+5-5 / x[sqroot(x+5)+sqroot(x)] but i dunno what to do next.
also this problem too.
lim cosx/cotx = cosx/(cosx/sinx)
x->pi/2
i cant split the problem because i just get (cosx)(cosx/sinx) and cant get either 1-cosx or sinx/x
x->4
i need help with this problem. I multiplied by the conjugate [sqroot(x+5)+sqroot(x)]/ [sqroot(x+5)+sqroot(x)] and got x+5-5 / x[sqroot(x+5)+sqroot(x)] but i dunno what to do next.
also this problem too.
lim cosx/cotx = cosx/(cosx/sinx)
x->pi/2
i cant split the problem because i just get (cosx)(cosx/sinx) and cant get either 1-cosx or sinx/x