Hint:Hi please can you help me with this question;
The LCM of a and b is 2^5 × 3^3 and the HCF of a and b is 2^2 × 3^2.
Given that a = 2^2 × 3^3 , find the value of b ?
EDITThe LCM of a and b is 2^5 × 3^3 and the HCF of a and b is 2^2 × 3^2.
Given that a = 2^2 × 3^3 , find the value of b ?
Did you follow those rules?Here are the rules: Write each number in prime factor form.
LCM:LCM: List all primes that appear in either number. Then take the highest power of each.
HCF:HCF: List only common primes. Then take the Least power of those.
Did you follow those rules?
Hi please can you help me with this question;
The LCM of a and b is 2^5 × 3^3 and the HCF of a and b is 2^2 × 3^2.
Given that a = 2^2 × 3^3 , find the value of b ?
Did you check against the given conditions?Thank you , Is this right , then.
b = 2^5 × 3^2 ?
How can i confirm this is right please ?
I do not grasp these rules.Here are the rules: Write each number in prime factor form.
\(LCM:\) List all primes that appear in either number. Then take the least power of each.
\(HCF:\) List only common primes. Then take the highest power of those.
Did you follow those rules?
Did you check against the given conditions?
If [MATH]a = 2^2 × 3^3[/MATH] and [MATH]b = 2^5 × 3^2[/MATH], the LCM is [MATH]2^5 × 3^3[/MATH], which is correct; and the HCF is [MATH]2^2 × 3^2[/MATH]. So you're right.
Why did you need to ask?
Here are the rules: Write each number in prime factor form.
\(LCM:\) List all primes that appear in either number. Then take the highest power of each.
\(HCF:\) List only common primes. Then take the Least power of those.
Did you follow those rules?
I do not believe anyone ever specified an algorithm for these processes at any time in my school career..EDIT
Subhotosh gave you the way to check it! a*b must equal LCM(a,b)*HCF(a,b)Thank you , Is this right , then.
b = 2^5 × 3^2 ?
How can i confirm this is right please ?
I am not sure what you are missing here based on your expertise that you constantly show on this website. Please don't be offended if what follows is already obvious to you.I do not grasp these rules.
Consider 60 = 2^2 * 3 * 5 and 90 = 2 * 3^2 * 5. The least power of each prime is 1, but 2 * 3 * 5 = 30 is not the least common multiple of 60 and 90. In fact 30 is not a multiple of either 60 or 90.
Am I misreading what you wrote?