Q1: An airplane travels N40∘E at an airspeed of 1000km/h. Measurement on the ground shows that the plane is travelling N45∘E at a speed of 1050 km/h. Calculate the velocity of the wind.
I know we use the formula Vg = Va + Vw
we know Vg is 1050km/h N45∘E
and Va is 1000km/h N40∘E
we don't know Vw, so we subtract it to the other side of the equation and we have a subtraction of vectors
I drew my vector diagram, and applied to cos law to get the veloctiy of the wind,
a= sqrt[1050^2 + 1000^2 -2(1000)(1050)cos∘]
and got 102.4 km/h as my wind velocity,
can someone confirm if i'm right? :s
Q2: solve for x given vector u=[3x, 7]; vector v= [5x, x]; the magnitude of vector u plus vector v = 10x
i added vector u and v and got [8x, x+7]
then did, 10x= sqrt[(8x)^2 + (x+7)^2] and solved for x
and got x as -1, but when i subbed in -1 and readded vector u and v and found the magnitude i didn't get back -10
I know we use the formula Vg = Va + Vw
we know Vg is 1050km/h N45∘E
and Va is 1000km/h N40∘E
we don't know Vw, so we subtract it to the other side of the equation and we have a subtraction of vectors
I drew my vector diagram, and applied to cos law to get the veloctiy of the wind,
a= sqrt[1050^2 + 1000^2 -2(1000)(1050)cos∘]
and got 102.4 km/h as my wind velocity,
can someone confirm if i'm right? :s
Q2: solve for x given vector u=[3x, 7]; vector v= [5x, x]; the magnitude of vector u plus vector v = 10x
i added vector u and v and got [8x, x+7]
then did, 10x= sqrt[(8x)^2 + (x+7)^2] and solved for x
and got x as -1, but when i subbed in -1 and readded vector u and v and found the magnitude i didn't get back -10
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