shefflebat
New member
- Joined
- Oct 15, 2005
- Messages
- 3
yeah..here is the thing i can't figure out how to do, exactly as it appears on my handout. uh..(pi) is just pi.
Suppose the circumference of the earth at the equator is the function (in terms or the radius r) C(r)=2(pi)r.
Suppose 1 foot is added to the end of a string that fits tightly about the equator and that string is held evenly above the surface of the earth. THe new circumference (in terms of the radius x) is N(x)=2(pi)x or just C(r)+1 foot.
Without finding a number for either r or the new radius x, find an expression that tells whether a mouse could run under the lengthened string.
Suppose the circumference of the earth at the equator is the function (in terms or the radius r) C(r)=2(pi)r.
Suppose 1 foot is added to the end of a string that fits tightly about the equator and that string is held evenly above the surface of the earth. THe new circumference (in terms of the radius x) is N(x)=2(pi)x or just C(r)+1 foot.
Without finding a number for either r or the new radius x, find an expression that tells whether a mouse could run under the lengthened string.
