Kinematics Problem

MarkFL said:
Given that is the time at which the bullet is leaving the barrel, then the position function \(x(t)\), evaluated at that time, will give you the length of the barrel, in meters.
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Thank you for all the help MarkFL. It is appreciated.
 
Ah. I think I get what we did here.

The first derivative of position is velocity. The second derivative of position is acceleration.

Since the problem gave us velocity, we had to integrate to find position but had to differentiate to find acceleration.

Can I approach every problem that does not give me position/velocity/acceleration with this mindset?
 
Yes by definition velocity is the time rate of change of position, and acceleration is the time rate of change of velocity.
 
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