benderzfloozy
New member
- Joined
- Apr 17, 2007
- Messages
- 18
Hi. I have done this problem but the answer is troubling me. Here is the problem:
Plot the function F(W,X,Y,Z) = summation symbol m(1,3,4,5,6,7,9,11,13). Use the K-map to simplify the function F. Also, display F in SOP form and display the complemented function ~F is SOP form.
What I've done:
The simplified equation I got was ~wz + ~wx + ~yz + w~xz. The ~ symbol refers to negation. Is this right?
The SOP form for F I got: w~x~yz + ~w~xyz + ~wx~y~z + ~wx~yz + ~wxy~z + ~wxyz + w~x~yz + w~xyz + wx~yz
The SOP form for ~F I got: wxy + w~z + ~w~x~z.
Could someone verify these? I would greatly appreciate it! Thnx.
Plot the function F(W,X,Y,Z) = summation symbol m(1,3,4,5,6,7,9,11,13). Use the K-map to simplify the function F. Also, display F in SOP form and display the complemented function ~F is SOP form.
What I've done:
The simplified equation I got was ~wz + ~wx + ~yz + w~xz. The ~ symbol refers to negation. Is this right?
The SOP form for F I got: w~x~yz + ~w~xyz + ~wx~y~z + ~wx~yz + ~wxy~z + ~wxyz + w~x~yz + w~xyz + wx~yz
The SOP form for ~F I got: wxy + w~z + ~w~x~z.
Could someone verify these? I would greatly appreciate it! Thnx.