y+y^2=t^(2)-4 I don't know how to solve for y
N nelidaperez New member Joined Oct 11, 2009 Messages 3 Oct 11, 2009 #1 y+y^2=t^(2)-4 I don't know how to solve for y
D Deleted member 4993 Guest Oct 11, 2009 #2 nelidaperez said: y+y^2=t^(2)-4 I don't know how to solve for y Click to expand... y[sup:2jfka01k]2[/sup:2jfka01k] + y -(t[sup:2jfka01k]2[/sup:2jfka01k] - 4) = 0 Treat the term (t[sup:2jfka01k]2[/sup:2jfka01k] - 4) as constant and solve the quadratic equation above.
nelidaperez said: y+y^2=t^(2)-4 I don't know how to solve for y Click to expand... y[sup:2jfka01k]2[/sup:2jfka01k] + y -(t[sup:2jfka01k]2[/sup:2jfka01k] - 4) = 0 Treat the term (t[sup:2jfka01k]2[/sup:2jfka01k] - 4) as constant and solve the quadratic equation above.
