The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph?
J jmoo New member Joined May 30, 2012 Messages 2 May 30, 2012 #1 The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph?
D Deleted member 4993 Guest May 30, 2012 #2 jmoo said: The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph? Click to expand... If you have a graph y = f(x) if you move it to right 'a' units, the equation of the new graph is y = f(x-a) Now your turn, show your work..... Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
jmoo said: The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph? Click to expand... If you have a graph y = f(x) if you move it to right 'a' units, the equation of the new graph is y = f(x-a) Now your turn, show your work..... Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 May 30, 2012 #3 jmoo said: The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph? Click to expand... http://www.purplemath.com/modules/fcntrans.htm
jmoo said: The graph of y=x^2 is shifted down 3 units and left 5 units. What is the equation of the new graph? Click to expand... http://www.purplemath.com/modules/fcntrans.htm
D Deleted member 4993 Guest May 30, 2012 #5 jmoo said: how about y=(x+5)^2 - 3 Click to expand... Looks good to me....