If i have a jar with 15 red, 13 yellow, and 7 green jelly beans what is the probability that i will pull out 1 red and 2 yellows (without the replacement of the ones i removed)
If i have a jar with 15 red, 13 yellow, and 7 green jelly beans,
what is the probability that i will pull out 1 red and 2 yellows
(without the replacement of the ones i removed)?
\(\displaystyle \text{If you mean Red-\!Yellow-\!Yellow }in\;that\;order\text{, the probability is: } \;\frac{15}{35}\cdot\frac{13}{34}\cdot\frac{12}{33} \;=\;\frac{78}{1309}\)
\(\displaystyle \text{If you mean 1 red, 2 yellows }in\;any\;order\text{, the probability is: }\; \dfrac{{15\choose1}{13\choose2}}{{35\choose3}} \;=\;\frac{1170}{6545} \;=\;\frac{234}{1309}\)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.