Iterated Integral

KEYWEST17

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Jan 19, 2011
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So far I have (x+y)^-2

Used U substitution

U=x+y
DU= 0+1 dx


y=3 to y=4 (U^-2) DU = U^-1/-1

(x+y)^-1/-1 from y=3 to y=4

From this point on I am stuck.
 

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1(x+y)2  dx  =  1x+y+f(y)\displaystyle \int \frac{1}{(x+y)^{2}}\;dx\;=\;-\frac{1}{x+y} + f(y)

1(x+y)2  dy  =  1x+y+g(x)\displaystyle \int \frac{1}{(x+y)^{2}}\;dy\;=\;-\frac{1}{x+y} + g(x)

Why are you substituting anything?
 
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