Isolating a variable

[Clifford]

Given these two equations I need to isolate the variable mbw. I subsituted v' into the second equation but as I try to work through it I get all tangled up and keep digging myself into a bigger hole. I was wondering if somebody could help me isolate mbw.

Thanks

\(\displaystyle \[
v'\; = \;\sqrt {\frac{{kx^2 }}
{{m_{bw} }}}
\]\)

\(\displaystyle \[
m_b v_b \; = \;m_{bw} v'
\]\)

 

[Denis]

Geeezzzz Clifford.....where did you get that "weirdo"?

Looks like we can do this:
Let a = m{bw} and b = m{b}v{b}
so equation becomes:
b = a sqrt(k x^2 / a) ; square both sides:
b^2 = a^2(k x^2) / a
b^2 = a k x^2
a = b^2 / (k x^2)

 

[morson]

Is \(\displaystyle m_b v_b\) one variable?

Also, what do you want \(\displaystyle m_{bw}\) to be in terms of?