Options are: A. stationary point B. maximum point C. minimum point
D. oblique tangent
I would say A is the correct answer (stationary point) by exclusion. Are the steps I took correct? I am not sure especially regarding finding mins and max.
Options are: A. stationary point B. maximum point C. minimum point D. oblique tangent View attachment 31077
I would say A is the correct answer (stationary point) by exclusion. Are the steps I took correct? I am not sure especially regarding finding mins and max.
Your work and answer are correct; some of the work is redundant, as you already know from the diagram that the derivative is positive everywhere but at x=-1, where is it zero. That shows that it is not a max or a min, and has a horizontal, not oblique, tangent, so it is a stationary point.
You also didn't really need the quadratic formula, as the derivative factors as [imath]e^x(x+1)^2[/imath]. And you didn't have to find the equation of the tangent line; knowing its slope is enough for the question (as I understand it -- it would be helpful if you stated the entire problem exactly, rather than giving it to us in pieces).
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