Is this really not possible?

[miiike]

Strange. Is there no way I may simplify or prove the below?

(A + C) (A' + B + C') to / equates to A'C + AC' +AB?


Ideas anyone?

 

[pka]

Strange. Is there no way I may simplify or prove the below?

(A + C) (A' + B + C') to / equates to A'C + AC' +AB?

No that is incomplete. There is a term missing.
It should be \(\displaystyle A'C + AC' +AB+CB\).

 

[miiike]

No that is incomplete. There is a term missing.
It should be \(\displaystyle A'C + AC' +AB+CB\).

Oh no. Then I'm stuck. Based on the answers I got from different people inc myself, we derive at:
A'C + AC' + AB + CB as the simplest form.

But somehow, my professor declares that the above expression may be simplified further to:
A'C + AC' +AB

That's the problem?

 

[pka]

Oh no. Then I'm stuck. Based on the answers I got from different people inc myself, we derive at: A'C + AC' + AB + CB as the simplest form.
But somehow, my professor declares that the above expression may be simplified further to:
A'C + AC' +AB

Is there any relationship between \(\displaystyle B~\&~C\) you have omitted?

 

[miiike]

Is there any relationship between \(\displaystyle B~\&~C\) you have omitted?

I do not know if there is a relationship btwn BC, but I do know that:

they r simply boolean expressions &
I was given the hint: XZ + XY + YZ' = XZ + YZ'

 

[Deleted member 4993]

Is "r" a variable?

Its a dependent variable - depending on your "age".....

 

[miiike]

Is "r" a variable?

You read into it too much already the 'i do know' part is not part of the question. I did not spell 'r' in full as 'are' that's all.

Kindly notify me if you see another way of working around the 2 expressions i provided, thank you