Is this factorable?

sarrudav

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Joined
Mar 27, 2010
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5
9x^2+12x+16

The entire problem is:

x/9x^2+12x+16 - 3x+4/27x^3-64

I need to find the LCD by factoring.
 
9x^2+12x+16

Not factorable.

Is it possible that you have a typo? Might it be 9x^2+24x+16? That is factorable to (3x + 4)^2.

Or 9x^2-24x+16? That is factorable to (3x - 4)^2.
 
Thank you. There is no chapter 4 in the whole book, so it is entirely possible that the rest of the book is not mistake-free. :D
 
sarrudav said:
9x^2+12x+16

The entire problem is:

x/9x^2+12x+16 - 3x+4/27x^3-64

I need to find the LCD by factoring.

\(\displaystyle \frac{x}{9x^2+12x+16} - \frac{3x+4}{(3x)^3 - (4)^3}\)

\(\displaystyle = \frac{x}{9x^2+12x+16} - \frac{3x+4}{(3x - 4)(9x^2+12x+16)}\)

\(\displaystyle = \frac{x(3x -4) - 3x - 4}{(3x - 4)(9x^2+12x+16)}\)
 
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