spacewater
Junior Member
- Joined
- Jul 10, 2009
- Messages
- 67
problem
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)
steps
\(\displaystyle f(x)= 3(x^2-4x+1)\)
this is farthest i got. How can I factor this problem?
find the zeros algebraically
\(\displaystyle f(x) = 3x^2-12x+3\)
steps
\(\displaystyle f(x)= 3(x^2-4x+1)\)
this is farthest i got. How can I factor this problem?