GetThroughDiffEq
New member
- Joined
- Mar 2, 2019
- Messages
- 23
I know this seems like a stupid question because if you did say 5000*.78 to get 3900, you'd just divide by .78 to get back 5000.
We're not going to use a calculator or software, so let's just assume your mind can't do division with large numbers (that is the point here):
What if I'm not a mathematical genius and wanted to know in a very fast time period (say 6 seconds) what to multiply 3900 by to get 5000?
I can guess and say 25%, sure, but it gets harder and harder if it's 562,705*.67 for instance.
What I'm getting at is can this be broken down to an algorithm where every number has the same proportion lost e.g. if 62000 loses 20% (62k*.8) then must gain x?
We're not going to use a calculator or software, so let's just assume your mind can't do division with large numbers (that is the point here):
What if I'm not a mathematical genius and wanted to know in a very fast time period (say 6 seconds) what to multiply 3900 by to get 5000?
I can guess and say 25%, sure, but it gets harder and harder if it's 562,705*.67 for instance.
What I'm getting at is can this be broken down to an algorithm where every number has the same proportion lost e.g. if 62000 loses 20% (62k*.8) then must gain x?