#1) (n=1 to n=oo) 2/(1+n^2) and #2) (n=0 to n=oo) (5^(2n)) / n! show steps plz
N NJ_84 New member Joined Apr 20, 2012 Messages 7 Apr 23, 2012 #1 #1) (n=1 to n=oo) 2/(1+n^2) and #2) (n=0 to n=oo) (5^(2n)) / n! show steps plz
pka Elite Member Joined Jan 29, 2005 Messages 11,990 Apr 23, 2012 #2 NJ_84 said: #1) (n=1 to n=oo) 2/(1+n^2) and #2) (n=0 to n=oo) (5^(2n)) / n! Click to expand... Because \(\displaystyle \frac{2}{1+n^2}<\frac{2}{n^2}\) use basic comparison. #2 Use limit comparison.
NJ_84 said: #1) (n=1 to n=oo) 2/(1+n^2) and #2) (n=0 to n=oo) (5^(2n)) / n! Click to expand... Because \(\displaystyle \frac{2}{1+n^2}<\frac{2}{n^2}\) use basic comparison. #2 Use limit comparison.
