IS MY SLOPE ANSWER RIGHT

G

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DID I DO THIS RIGHT, I JUST NEED A YES OR NO.

The slope of the tangent line of a curve is given by F(x) = x^2-5x+5

If the point (0, 4) is on the curve.


(1/3)x^3 - 6x^2 + 5x + 4
 
Slope is derivative not anti-derivative!
Find F'(x).
 
achiles i just tried it and i got something different. I got

f(x) = (1/3)x^3 - (5/2)x^2 + 5x + 4

keep trying buddy!
 
achillesg22 said:
DID I DO THIS RIGHT, I JUST NEED A YES OR NO.
Click to expand...
It appears you need more than that.

The slope of the tangent line of a curve is given by F(x) = x^2-5x+5
Click to expand...
You are given the derivative. Plug it in. F(0) = 5
 
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