Hello 38175425. Your work is good, but you're not done. So far, you've answered:Is my answer to this … correct?
Darn, and I thought that a=12 was correct!Hello 38175425. Your work is good, but you're not done. So far, you've answered:
f(3) = ?
We're told the limit at 3 exists; therefore, function f must be continuous at x=3.
If you're still stuck, then sketch a rough graph of f(x) from x=0 to x=5, using the incorrect value a=12, and see what goes wrong at x=3.
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