investments: S investe $2K more than L @ 2% higher rate

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B.P.

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Mar 24, 2009
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Scott and laura have both invested some money. Scott invested 3000 more than laura and at 2% higher interest rate. if Scott received $8oo annual interest and laura received #400, how much did Scott invest?

type / rate / amount / income
x% / xr / xa / 400
x%+ 2% / xr+.02 / 3000+xa / 800

I don't know how to set this problem up I also don't know if I have the information set up right
 
Re: investment word problems

B.P. said:
Scott and laura have both invested some money. Scott invested 3000 more than laura and at 2% higher interest rate. if Scott received $8oo annual interest and laura received #400, how much did Scott invest?

type / rate / amount / income
x% / xr / xa / 400
x%+ 2% / xr+.02 / 3000+xa / 800

I don't know how to set this problem up I also don't know if I have the information set up right
Click to expand...
No idea what you're trying to do with that set-up; sorry.

A = amount invested by Laura; then A+3000 = amount invested by Scott. Follow that?

R = rate received by Laura; then R + .02 = rate received by Scott. Still with me?

SO we have:
Laura: A*R = 400
Scott: (A+3000)*(R+.02) = 800

All yours to wrap up :wink:
 
Re: investment word problems

so do I substitute Laura's equation into Scott's equation? if so I got R = 400-A so A + 3000 + 400 - A+ .02 =800? do I just add them all up?
 
I turned A + R = 400 to R= 400 - A by moving A to the other side so I could substitute the equation into the R's place in (A + 3000) + (R + .02) = 800. I don't really know what else I'd do to solve a word problem with two equations like A + R = 400 and (A + 3000) + (R + .02) = 800.
 
B.P. said:
I turned A + R = 400 to R= 400 - A ....
Click to expand...
BUT it's NOT A + R = 400, it's A*R = 400 : A times R ; so R = 400/A : kapish?
 
...I've got bad eyesight so that little symbol looked like a plus to me, It makes more sense now that I know its a multiplication symbol.
 
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