Invertible matrices problems

diogomgf

Junior Member
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Oct 19, 2018
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127
Hello everyone,

I have a linear algebra problem that I need help with, and another problem I think solved but I'm not 100% sure and the book doesn't have the solution for it.
The problems are as follow:

1- \(\displaystyle A, B \) are matrices \(\displaystyle \in M_{n*n} \), with \(\displaystyle A\) being invertible. Show that \(\displaystyle A + B \) and \(\displaystyle I_n + BA^{-1} \) are either both invertible or both non-invertible.

I don't really know where to start on this problem... If some one could hint me in the right direction...

2- Let \(\displaystyle A, B \) be matrices \(\displaystyle \in M_{n*n} \) such that \(\displaystyle A, B \) and \(\displaystyle A-B \) are all invertible. Justify that \(\displaystyle B^{-1} - A^{-1} \) is also invertible.

For this one I did as follow:

\(\displaystyle ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = I_n \Leftrightarrow B \cdot ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow \)

\(\displaystyle \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} \cdot ( B^{-1} - A^{-1} ) = B \cdot ( B^{-1} - A^{-1} ) \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot I_n = I_n - B \cdot A^{-1} \Leftrightarrow \)

\(\displaystyle \Leftrightarrow I_n - B \cdot A^{-1} = I_n - B \cdot A^{-1} \).

Not sure if the solution is this, and I'd hope any one could correct me otherwise...
Also, my apologies if the LaTeX notations are not correct.

Thanks,
Diogo
 
1) Is actually pretty straightforward when you apply method to it.

a) Assume \(\displaystyle A+B\) is invertible, noting that \(\displaystyle A\) is invertible show that \(\displaystyle (I_n +BA^{-1})A\) is invertible
and thus \(\displaystyle I_n + B A^{-1}\) is invertible

b) Assume \(\displaystyle I_n + B A^{-1}\) is invertible, and apply pretty much the same logic as in (a) to show \(\displaystyle A+B\) is invertible
 
1) Is actually pretty straightforward when you apply method to it.

a) Assume \(\displaystyle A+B\) is invertible, noting that \(\displaystyle A\) is invertible show that \(\displaystyle (I_n +BA^{-1})A\) is invertible
and thus \(\displaystyle I_n + B A^{-1}\) is invertible

b) Assume \(\displaystyle I_n + B A^{-1}\) is invertible, and apply pretty much the same logic as in (a) to show \(\displaystyle A+B\) is invertible

Thanks for the tip! That makes it alot easier 8-)

Cheers,
Diogo
 
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