Hello everyone,
I have a linear algebra problem that I need help with, and another problem I think solved but I'm not 100% sure and the book doesn't have the solution for it.
The problems are as follow:
1- \(\displaystyle A, B \) are matrices \(\displaystyle \in M_{n*n} \), with \(\displaystyle A\) being invertible. Show that \(\displaystyle A + B \) and \(\displaystyle I_n + BA^{-1} \) are either both invertible or both non-invertible.
I don't really know where to start on this problem... If some one could hint me in the right direction...
2- Let \(\displaystyle A, B \) be matrices \(\displaystyle \in M_{n*n} \) such that \(\displaystyle A, B \) and \(\displaystyle A-B \) are all invertible. Justify that \(\displaystyle B^{-1} - A^{-1} \) is also invertible.
For this one I did as follow:
\(\displaystyle ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = I_n \Leftrightarrow B \cdot ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow \)
\(\displaystyle \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} \cdot ( B^{-1} - A^{-1} ) = B \cdot ( B^{-1} - A^{-1} ) \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot I_n = I_n - B \cdot A^{-1} \Leftrightarrow \)
\(\displaystyle \Leftrightarrow I_n - B \cdot A^{-1} = I_n - B \cdot A^{-1} \).
Not sure if the solution is this, and I'd hope any one could correct me otherwise...
Also, my apologies if the LaTeX notations are not correct.
Thanks,
Diogo
I have a linear algebra problem that I need help with, and another problem I think solved but I'm not 100% sure and the book doesn't have the solution for it.
The problems are as follow:
1- \(\displaystyle A, B \) are matrices \(\displaystyle \in M_{n*n} \), with \(\displaystyle A\) being invertible. Show that \(\displaystyle A + B \) and \(\displaystyle I_n + BA^{-1} \) are either both invertible or both non-invertible.
I don't really know where to start on this problem... If some one could hint me in the right direction...
2- Let \(\displaystyle A, B \) be matrices \(\displaystyle \in M_{n*n} \) such that \(\displaystyle A, B \) and \(\displaystyle A-B \) are all invertible. Justify that \(\displaystyle B^{-1} - A^{-1} \) is also invertible.
For this one I did as follow:
\(\displaystyle ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = I_n \Leftrightarrow B \cdot ( B^{-1} - A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} = B \Leftrightarrow \)
\(\displaystyle \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot ( B^{-1} - A^{-1} )^{-1} \cdot ( B^{-1} - A^{-1} ) = B \cdot ( B^{-1} - A^{-1} ) \Leftrightarrow ( I_n - B \cdot A^{-1} ) \cdot I_n = I_n - B \cdot A^{-1} \Leftrightarrow \)
\(\displaystyle \Leftrightarrow I_n - B \cdot A^{-1} = I_n - B \cdot A^{-1} \).
Not sure if the solution is this, and I'd hope any one could correct me otherwise...
Also, my apologies if the LaTeX notations are not correct.
Thanks,
Diogo