inverse matrices

SONCEE

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Joined
Dec 8, 2008
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10
show that the following matrices are inverse of each other.

[1,2 ] [ -3 , 1 ]
[4,6] [2 , 1/2]
 
A two-by-two is easy to find the inverse of:

If \(\displaystyle A=\begin{bmatrix}a&b\\c&d\end{bmatrix}\)

\(\displaystyle A^{-1}=\frac{1}{det(A)}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}\)
 
As posted, they are not inverses.
Did you mean \(\displaystyle \left[ {\begin{array}{rr} { - 3} & 1 \\ 2 & { {-} \frac{1}{2}} \\ \end{array} } \right]\)??
 
pka said:
As posted, they are not inverses.
Did you mean \(\displaystyle \left[ {\begin{array}{rr} { - 3} & 1 \\ 2 & { {-} \frac{1}{2}} \\ \end{array} } \right]\)??
yes i did, i'm sorry i wrote it wrong
 
If you multiply those two together do you get \(\displaystyle \left[ {\begin{array}{rr} 1 & 0 \\ 0 & 1 \\ \end{array} } \right]\)?
 
Use the fact that:

If

\(\displaystyle [A]\cdot \, = \)

then

\(\displaystyle \, = \, [A]^{-1}\)
 
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