Inverse Laplace transform of a function

Punch

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Nov 29, 2015
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I can't seem to find the ways to solve the inverse laplace transform of: s2+2s2+2s+5\displaystyle \, \dfrac{s^2\, +\, 2}{s^2\, +\, 2s\, +\, 5}

I used completing square to make it become: s2+2(s+1)2+4\displaystyle \, \dfrac{s^2\, +\, 2}{(s\, +\, 1)^2\, +\, 4}

The inverse laplace transform of: 2(s+1)2+4\displaystyle \, \dfrac{2}{(s\, +\, 1)^2\, +\, 4}
is e-t sin2t.

I am struck with: s2(s+1)2+4\displaystyle \, \dfrac{s^2}{(s\, +\, 1)^2\, +\, 4}

I do not know what to do next.

The final answer is ?(t) -(e-t/2 )(4cos2t + sin2t). However, I don't understand what the Dirac delta function is for. Can you guys help me? Thanks in advance.
 
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