Hello,For this question:f(x) = e^2x and g(x) = 3/2 In(x)Find (fog) (x) and hence solve (fog)(x) = 3I got up to (fog)(x) = e^3In (x) and I don't know how to continueThanks in advance!
Hello,For this question:f(x) = e^2x and g(x) = 3/2 In(x)Find (fog) (x) and hence solve (fog)(x) = 3I got up to (fog)(x) = e^3In (x) and I don't know how to continueThanks in advance!
First I'll add some parenthesis to make more clear the functions. Hopefully I'll add them in the correct place.
f(x) = e^(2 x) = \(\displaystyle e^{2 x}\)
g(x) = (3/2) ln(x) = \(\displaystyle \frac{3}{2} ln(x)\)
I believe this is consistent with what you have
(fog)(x) = \(\displaystyle e^{3\, ln(x)}\)
You now need some of the rules of logarithms:
a log(b) = log(ba)
and
aloga(b) = b
Oh and ln(x) = loge(x)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.