inverse functions

abcdgirl

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Joined
Dec 14, 2009
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Need help graphing inverse functions. for ex. graphing 1/4y-3/4=x this is f-1(x) while f(x)=4x+3
what is the inverse of f(x)=square root of x +1 (small 3 outside the square root
 
abcdgirl said:
...1/4y-3/4=x ...
Your typing is a bit difficult to follow...
is that (1/4)y - 3/4 = x?
If so, then: y/4 - 3/4 = x ; y - 3 = 4x ; y = 4x + 3 which means slope=4 and y-intercept=3 ; got that?
 
abcdgirl said:
Need help graphing inverse functions. for ex. graphing 1/4y-3/4=x this is f-1(x) while f(x)=4x+3
what is the inverse of f(x)=square root of x +1 (small 3 outside the square root

Hi abcdgirl,

Are you asking for the inverse of \(\displaystyle f(x)=\sqrt[3]{x+1}\)

Does 'small 3 outside the square root' mean 'cube root'??
 
Denis said:
abcdgirl said:
...1/4y-3/4=x ...
Your typing is a bit difficult to follow...
is that (1/4)y - 3/4 = x?
If so, then: y/4 - 3/4 = x ; y - 3 = 4x ; y = 4x + 3 which means slope=4 and y-intercept=3 ; got that?

Do you know how to graph the function and the inverse of the function
 
abcdgirl said:
If so, then: y/4 - 3/4 = x ; y - 3 = 4x ; y = 4x + 3 which means slope=4 and y-intercept=3 ; got that?

Do you know how to graph the function and the inverse of the function

Draw the function y=4x+3 by taking two points . . .

The Inverse is the Symmetry of f(x) with respect to y=x . . .
 
="masters"]
Hi abcdgirl,

Are you asking for the inverse of \(\displaystyle f(x)=y=\sqrt[3]{x+3}\)

Interchange your x and y.

\(\displaystyle x=\sqrt[3]{y+3}\)

Solve for y.

\(\displaystyle x^3=y+3\)

\(\displaystyle y=x^3-3\)


Does 'small 3 outside the square root' mean 'cube root'??

abcdgirl said:
Yes I just don't know how to use make the square roots with my keyboard

To get \(\displaystyle f(x)=y=\sqrt[3]{x+3}\), you type
Code:
[tex]f(x)=y=\sqrt[3]{x+3}[/tex]
 
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