Your typing is a bit difficult to follow...abcdgirl said:...1/4y-3/4=x ...
abcdgirl said:Need help graphing inverse functions. for ex. graphing 1/4y-3/4=x this is f-1(x) while f(x)=4x+3
what is the inverse of f(x)=square root of x +1 (small 3 outside the square root
Denis said:Your typing is a bit difficult to follow...abcdgirl said:...1/4y-3/4=x ...
is that (1/4)y - 3/4 = x?
If so, then: y/4 - 3/4 = x ; y - 3 = 4x ; y = 4x + 3 which means slope=4 and y-intercept=3 ; got that?
abcdgirl said:If so, then: y/4 - 3/4 = x ; y - 3 = 4x ; y = 4x + 3 which means slope=4 and y-intercept=3 ; got that?
Do you know how to graph the function and the inverse of the function
="masters"]
Hi abcdgirl,
Are you asking for the inverse of \(\displaystyle f(x)=y=\sqrt[3]{x+3}\)
abcdgirl said:Yes I just don't know how to use make the square roots with my keyboard
[tex]f(x)=y=\sqrt[3]{x+3}[/tex]