H help7244 New member Joined Aug 18, 2009 Messages 6 Aug 19, 2009 #1 solve for y: ln(y+3)=x^2 i just forget how to solve it but im pretty sure you need the inverselog function...
solve for y: ln(y+3)=x^2 i just forget how to solve it but im pretty sure you need the inverselog function...
L Loren Senior Member Joined Aug 28, 2007 Messages 1,298 Aug 19, 2009 #2 What happens if you use the definition of log? \(\displaystyle \ln_eN=x >>> e^x = N\)
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,116 Aug 19, 2009 #3 help7244 said: solve for y: ln(y+3)=x^2 i just forget how to solve it but im pretty sure you need the inverselog function... Click to expand... Change to exponential form. If ln(y + 3) = x[sup:16yqhw01]2[/sup:16yqhw01], then y + 3 = e^(x[sup:16yqhw01]2[/sup:16yqhw01]) Now, if you add -3 to both sides, that should give you y by itself on the left side of the equation.
help7244 said: solve for y: ln(y+3)=x^2 i just forget how to solve it but im pretty sure you need the inverselog function... Click to expand... Change to exponential form. If ln(y + 3) = x[sup:16yqhw01]2[/sup:16yqhw01], then y + 3 = e^(x[sup:16yqhw01]2[/sup:16yqhw01]) Now, if you add -3 to both sides, that should give you y by itself on the left side of the equation.
