Inverse function

[SamanthaMFR]

What is the inverse function of f(x)=(6/x)+1?

 

[Deleted member 4993]

What is the inverse function of f(x)=(6/x)+1?

What are your thoughts?

If you are stuck at the beginning tell us and we'll start with the definitions.

Please share your work with us ... even if you know it is wrong

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Hint:

First step is to interchange x↔y in the given expression and then solve for 'y'.

 

[SamanthaMFR]

Answer

For me the answer is

f(x)=(6/x)+1
y=(6/x)+1
x=(6/y)+1


y=(6+1)/x

 

[Mrspi]

For me the answer is

f(x)=(6/x)+1
y=(6/x)+1
x=(6/y)+1<------correct to here......


y=(6+1)/x

Ok....now, how did you go about solving

x = (6/y) + 1

for y?

Please show us your work, so we can determine where you made your mistake.

HINT: Personally, I would begin by subtracting 1 from both sides of the equation:

x - 1 = (6/y) + 1 - 1
x - 1 = (6/y)

Can you continue to solve this for y?

 

[SamanthaMFR]

Another Answer

is it?
x - 1 = (6/y) + 1 - 1
x - 1 = (6/y)
(x-1)*y=6
y=6/(x-1)

 

[Deleted member 4993]

is it?
x - 1 = (6/y) + 1 - 1
x - 1 = (6/y)
(x-1)*y=6
y=6/(x-1)

Correct!

The way to check your answer for inverse function is to use the identity:

f[f^-1(x)] = f^-1[f(x)] = x