Monkeyseat
Full Member
- Joined
- Jul 3, 2005
- Messages
- 298
Just wondering if you could check my working for me below. I *think* it's right but when I put it in on an equation calculator to check and it seems to think that x is just 0 but that might just be it only giving one value (origin). Regardless, I'm mainly interested in whether I re-arranged it for x correctly and factorised it correctly, not just the answer.
Question:
Working:
This was just the start of the question for finding the area bound by the curve and the line which I have done, but was unsure here (on the easier bit hehe
) for some odd reason.
Anyway, thanks for any help. I know it can also factorise to x(x-4) if you do the steps a bit differently at the start by doubling to get 1 whole x, squaring both sides and then re-arranging. That also gives 4 but I just wanted to check.
Yeah it's a bit basic, sorry, but thanks for checking. Oh and by sqr. I mean square root if that's not clear.
Not sure if this was the right board on here to post it on but cheers.
Question:
Find the point of intersection of the curve y = sqr.x and y = 1/2x other than the origin.
Working:
Equate both formulas:
1/2x = sqr.x
Square both sides:
1/4x^2 = x
Move all x to one side:
0 = x - 1/4x^2
Factorise x out:
0 = x(1-1/4x)
----
x = 0, but other than the origin, the othe point of intersection is:
(1-1/4x) = 0
1 = 1/4x
Multiply by 4:
4 = x
x = 4
----
When x = 4:
y = sqr.x
y = sqr.4
y = 2
Therefore point = (4,2)
This was just the start of the question for finding the area bound by the curve and the line which I have done, but was unsure here (on the easier bit hehe
Anyway, thanks for any help. I know it can also factorise to x(x-4) if you do the steps a bit differently at the start by doubling to get 1 whole x, squaring both sides and then re-arranging. That also gives 4 but I just wanted to check.
Yeah it's a bit basic, sorry, but thanks for checking. Oh and by sqr. I mean square root if that's not clear.
Not sure if this was the right board on here to post it on but cheers.