intermediate value theorem

orangecrush

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Sep 11, 2006
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Here's the question. It's a theoretical one, i'm supposed to prove it exists, but will not find an actual number.

Two fishermen are ice fishing in the middle of the lake. One leaves at 6:00pm and walks back to camp along a scenic route, taking two and a half hours to get back. The second one leaves at 7:00pm, walks on a direct route back to camp and takes an hour to get there. Show that there was a time where they were equidistant from camp.

What I've got so far is that there are two distant graphs, fisherman one and fisherman two. I have to somehow combine the two graphs to make one function. Using the intermediate value theorem, then one value should be positive and one negative in order to have a value of zero somewhere on the one graph. Subtracting one graph from another and getting a value of zero means that somewhere on the graph, the two are equal. But I don't know how to prove that with no values....how do I show that there was a time where they were equidistant from camp??
 
Here's my guess:

The one guy -- let's call him "A" -- started walking at 6 and finished at 8:30. The other, "B", started walking at 7 and finished at 8.

Suppose the fishing hole is distance "D" from the camp.

Consider the function F(t) = (distance of B from camp) - (distance of A from camp), where "t = 0" is 6pm. Then:

. . . . .F(0) = 0

. . . . .F(1) > 0 (because B hasn't started yet, but A has)

. . . . .F(2) < 0 (because B is back at camp, and A isn't)

. . . . .F(2.5) = 0

What can you conclude?

Eliz.
 
That makes sense. That means F(1) is some bigger number minus some smaller number, giving a positive value. And F(2) is zero minus some number, giving a negative number.
Thank you.
 
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