intermediate algebra

[horsewoman27]

Suppose that the number of bacteria in a certain population increases according to an exponential growth model. A sample of 2600 bacteria selected from this population reached the size of 2873 bacteria in two and a half hours. Find the continuous growth rate per hour. Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

I got:
2873 = 2600 e^(2.5r)

ln(2873 / 2600) = 2.5r

[ln(2873 / 2600)] / 2.5 = r
r=0.0399381
it says to round the percentage to the nearest hundreth. any help

 

[Deleted member 4993]

Suppose that the number of bacteria in a certain population increases according to an exponential growth model. A sample of 2600 bacteria selected from this population reached the size of 2873 bacteria in two and a half hours. Find the continuous growth rate per hour. Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

I got:
2873 = 2600 e^(2.5r)

ln(2873 / 2600) = 2.5r

[ln(2873 / 2600)] / 2.5 = r
r=0.0399381
it says to round the percentage to the nearest hundreth. any help

Where exactly do you need help?

converting 'r' to percentage?