intermediate algebra

[hopen2impov]

(1/3)^3 +5/27 -1/3 x(1/9)^2
1/27 +5/27 -1/3 x^2/81
6/27 -1/3 =14/27 x^2/81
14/27 x^2/81
answer 14x^2/3, is this correct?

 

[Deleted member 4993]

(1/3)^3 +5/27 -1/3 x(1/9)^2
1/27 +5/27 -1/3 x^2/81<<<<< Square (^2) is only on (1/9) - thus you should not have x^2
6/27 -1/3 =14/27 x^2/81
14/27 x^2/81
answer 14x^2/3, is this correct? <<< No