intermediate algebra

[hopen2impov]

multiply and simplify

(a^2 b^3 c / 2b^2 c^3)^4
a^16 b^36 c / 2 b^8 c^36
a^16 b^4 c/2 b^1 c^36
answer a^16 b^5 c^36

 

[masters]

multiply and simplify

(a^2 b^3 c / 2b^2 c^3)^4
a^16 b^36 c / 2 b^8 c^36
a^16 b^4 c/2 b^1 c^36
answer a^16 b^5 c^36

Hi hopen2improv,

I'm assuming: \(\displaystyle \left(\frac{a^2b^3c}{2b^2c^3}\right)^4=\frac{a^8b^{12}c^4}{16b^8c^{12}}=\)

If that's it, can you finish?

 

[Deleted member 4993]

multiply and simplify

(a^2 b^3 c / 2b^2 c^3)^4
a^16 b^36 c / 2 b^8 c^36
a^16 b^4 c/2 b^1 c^36
answer a^16 b^5 c^36 <<< incorrect

You need to learn to use grouping correctly - using PEMDAS. Otherwise it is very difficult to interpret your posted problem.

Also please review and practice laws of exponents. Go to:

http://www.purplemath.com/modules/exponent.htm

As I interpret it - your problem is to simplify:

\(\displaystyle \left [ \frac{a^2b^3c}{2b^2c^3}\right ]^4\)

if that is so - you should have written it as:

[(a^2 b^3 c) / (2b^2 c^3)]^4

The parentheses in red are needed to complete grouping. As you wrote it, it means:

(a^2 b^3 c / 2b^2 c^3)^4

\(\displaystyle (a^2 \ b^3 \ \frac{c}{2} \ b^2 \ c^3)^4\)

 

[hopen2impov]

i wrote the problem correctly out the book with no mistakes.

(a^2 b^3 c / 2 b^2 c^3)^4 this is how the problem look in the math book. There's no brackets.
is the answer a^16 c/8 b^16 c^3

 

[mmm4444bot]

(a^2 b^3 c / 2 b^2 c^3)^4 this is how the problem look in the math book. There's no brackets.

I don't believe it, but, if this claim is actually true, then I think that your book is crap.

Regardless, WE require that you use proper grouping symbols, if you want help from these boards.

To learn how to properly type math expressions, check out THIS SITE.



:!: You did not show any of your work, so neither will I. Kapish?



[(a^2 b^3 c)/(2 b^2 c^3)]^4 = (a^8 b^4)/(16 c^8)

 

[masters]

Re:

(a^2 b^3 c / 2 b^2 c^3)^4 this is how the problem look in the math book. There's no brackets.

I don't believe it, but, if this claim is actually true, then I think that your book is crap.

Regardless, WE require that you use proper grouping symbols, if you want help from these boards.

To learn how to properly type math expressions, check out THIS SITE.



:!: You did not show any of your work, so neither will I. Kapish?



[(a^2 b^3 c)/(2 b^2 c^3)]^4 = (a^8 b^4)/(16 c^8)

Actually, if that is truly the way it appears in the text, then Subotosh Khan has the correct setup.

\(\displaystyle \left(a^2\:b^3\:\frac{c}{2}\:b^2\:c^3\right)^4=\frac{a^8b^{12}c^4b^8c^{12}}{16}=\frac{a^8b^{20}c^{16}}{16}\)