multiply and simplify (1/3x^4)(2/3x^3) 4/12x*6/9x
H hopen2impov Junior Member Joined Aug 4, 2010 Messages 66 Aug 25, 2010 #1 multiply and simplify (1/3x^4)(2/3x^3) 4/12x*6/9x
M masters Full Member Joined Mar 30, 2007 Messages 378 Aug 25, 2010 #2 hopen2impov said: multiply and simplify (1/3x^4)(2/3x^3) 4/12x*6/9x Click to expand... Hi hopen2improv, I'm interpreting your grouping this way: \(\displaystyle \left(\frac{1}{3x^4}\right)\left(\frac{2}{3x^3}\right)\) \(\displaystyle \left(\frac{1}{3x^4}\right)\left(\frac{2}{3x^3}\right)=\frac{2}{9x^7}\) Or, it could be \(\displaystyle \left(\frac{1}{3}x^4\right)\left(\frac{2}{3}x^3\right)=\frac{2}{9}x^7\) Is your second line an attempt at an answer to the first line, or is it a separate problem? If it's a separate problem, is it \(\displaystyle \frac{4}{12x^6} \div 9x\)
hopen2impov said: multiply and simplify (1/3x^4)(2/3x^3) 4/12x*6/9x Click to expand... Hi hopen2improv, I'm interpreting your grouping this way: \(\displaystyle \left(\frac{1}{3x^4}\right)\left(\frac{2}{3x^3}\right)\) \(\displaystyle \left(\frac{1}{3x^4}\right)\left(\frac{2}{3x^3}\right)=\frac{2}{9x^7}\) Or, it could be \(\displaystyle \left(\frac{1}{3}x^4\right)\left(\frac{2}{3}x^3\right)=\frac{2}{9}x^7\) Is your second line an attempt at an answer to the first line, or is it a separate problem? If it's a separate problem, is it \(\displaystyle \frac{4}{12x^6} \div 9x\)
