Intermediate Algebra: Solve 7x^2 + 5x + 3 = 0

Helen

Junior Member
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Oct 28, 2007
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106
Find the imaginary solutions of the equation.
This is the problem: 7x ^ (2) + 5x +3 = 0
This is my answer:
{-5 + i sqrt(59), 5 - i sqrt (59)}
over 7--------------------7
Is this answer correct?
 
Re: Intermediate Algebra

Almost. Your 5 in each root should be positive. And 2a is your denominator, thus 14 instead of 7.
 
Re: Intermediate Algebra

You mean 5's are negative, right masters?

7x^2 + 5x + 3 = 0

x = [-5 +- sqrt(5^2 - 4 * 7 * 3)] / (2 * 7)
x = [-5 +- sqrt(-59)] / 14
x = [-5 +- i * sqrt(59)] / 14
 
Re: Intermediate Algebra

Masters and Denis,
Thank you both for your help. Helen
 
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